ACE TEST SERIES QUESTION ON SLIDING WINDOW PROTOCOL

Shankar Kakde asked Jan 23, 2019

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Shankar Kakde asked Jan 23, 2019

Shankar Kakde

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OneZero

commented Jan 24, 2019

W.Tx = Tx + 2Tp

W = 1 + 2a

given W = 5

therefore 1 + 2a = 5

now for stop and wait

eff = Tx/(Tx + 2Tp)

eff = 1/(1 + 2a)

eff = 1/5 = 20%

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answer should be 20 %

Rajat Negi answered Jan 24, 2019

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