Use Binomial distribution:-

In which $Var = npq$

Here, $n = 3, p = \frac{1}{3}, q = \frac{2}{3}$

Pluggin the values into the above formula you will get $Var = 0.66$.

In which $Var = npq$

Here, $n = 3, p = \frac{1}{3}, q = \frac{2}{3}$

Pluggin the values into the above formula you will get $Var = 0.66$.