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Find how much disk space (in surfaces) will be required to store 300,000 120-byte logical records, if the disk is fixed sector with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore any file header records and track indices and assume that records cannot span two sectors.
The solution is:
Each sector can hold 4 logical records.
The required number of sectors is 303,150/4 = 75,788 sectors
= 75,788/96 tracks = 790 track
= 790/110 = 8 surfaces.
How come number of records is 303150 rather than 300000? Please explain.
in Operating System by (49 points) | 52 views

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