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Permutation [closed]

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The number of ways can 5 letter be put into 3 letter boxes A, B, C if letter box A must contain atleast 2 letters ________.

 

Please tell what are the extra cases in this:

Choose 2 letters and put in box A – $^5C_2$

Now remaining 3 letters have $3^3$ choices

So, $^5C_2 \times 3^3 = 270$

in Numerical Ability by Active (2.2k points)
closed by | 146 views
0
Should be 270 , what's the answer?
0
answer is 131 and it is correct
0
only if letters were non-distinct . what r u considernig here?

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