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The number of ways can 5 letter be put into 3 letter boxes A, B, C if letter box A must contain atleast 2 letters ________.

Please tell what are the extra cases in this:

Choose 2 letters and put in box A – $^5C_2$

Now remaining 3 letters have $3^3$ choices

So, $^5C_2 \times 3^3 = 270$

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Should be 270 , what's the answer?
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answer is 131 and it is correct
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only if letters were non-distinct . what r u considernig here?