2 votes 2 votes void foo(int n) { for(i1=1;i1<=n;i1++) { for(i2=1;i2<=i1;i2++) { ....... { for(i6=1;i6<=i5;i6++) { count++; } } } } } Count initially 0.What is value returned by foo(8)? Programming in C programming-in-c programming made-easy-test-series + – srestha asked Jan 28, 2019 edited Mar 3, 2019 by ajaysoni1924 srestha 621 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Shobhit Joshi commented Jan 28, 2019 reply Follow Share $\frac{n*(n+1)*(n+2)*(n+3)*(n+4)*(n+5)}{1.2.3.4.5.6}$ is this the answer ? 1 votes 1 votes srestha commented Jan 28, 2019 reply Follow Share yes ans $\binom{13}{6}$ how u done plz tell procedure @Shobhit Joshi 0 votes 0 votes Shobhit Joshi commented Jan 28, 2019 reply Follow Share $S_1=n$ , if there was only $1$ for loop $S_2=\sum_{1}^{n} n=\frac{n*(n+1)}{1*2}$ , if there were $2$ for loop $S_3=\sum_{1}^{n}S_2=\frac{n*(n+1)*(n+2)}{1*2*3}$ , if there were $3$ for loop similarly, $S_6=\sum_{1}^{n}S_5=\frac{n*(n+1)*(n+2)*(n+3)*(n+4)*(n+5)}{1*2*3*4*5*6}$ , if there were $6$ for loop That's how i did it 6 votes 6 votes aambazinga commented Jan 28, 2019 reply Follow Share @Shobhit Joshi's answer is nice. I just want to add that, this type of loop is a general form for computing (n+r-1)C(r), here n=8, r=6. 0 votes 0 votes Shobhit Joshi commented Jan 28, 2019 i edited by Shobhit Joshi Jan 28, 2019 reply Follow Share @aambazinga thanks, i will try to remember ! 0 votes 0 votes pradeepchaudhary commented Mar 8, 2019 reply Follow Share 1716 is the answer.... 0 votes 0 votes Please log in or register to add a comment.