1 votes 1 votes A 1 Mbps satellite link connects two ground stations. The altitude of the satellite is 6000 km and speed of the signal is 3 × 10^8 m/s. What should be the packet size for a channel utilization of 50% for a satellite link using go-back-63 sliding window protocol? Assume that the acknowledgment packets are negligible in size and that there are no errors during communication. 81031 Bytes 83101 Bytes 801301 Bytes 81301 Bytes Computer Networks sliding-window computer-networks made-easy-test-series + – Badayayash asked Jan 28, 2019 recategorized Mar 3, 2019 by ajaysoni1924 Badayayash 802 views answer comment Share Follow See all 8 Comments See all 8 8 Comments reply Show 5 previous comments Gupta731 commented Jan 28, 2019 reply Follow Share Dont trust made easy answers. 0 votes 0 votes Badayayash commented Jan 28, 2019 reply Follow Share @balchandar reddy san yea then ans becomes 79.68 thank you for pointing it out actually in made easy they took 62 that's why i mistakenly used 62 0 votes 0 votes ronak.ladhar commented May 12, 2020 reply Follow Share It is actually whole 80 not 79.68. 0 votes 0 votes Please log in or register to add a comment.