The Gateway to Computer Science Excellence
0 votes
125 views

What is the minimum difference between two successive real numbers representable in this system?

in Digital Logic by Active (4.9k points) | 125 views
0
minimum= $2^{-40}$

maximum= $2^{22}$
0
Nope. Maximum = 2^22
0
0
ohh sry i wrongly checked i though there are 5 bits in exponent. Now check minimum will be same but i corrected maximum.
0

@Shubhgupta how minimum is 2^-40?

I am getting this

+1

First small- $(1+000000000*2^{-9})*2^{0-31}= 1*2^{-31}= 2^{-31}$

Second small- $(1+000000001*2^{-9})*2^{0-31}= 1*2^{-31}+ 1*2^{-9}*2^{-31}= 2^{-31}+2^{-40}$

Difference - $2^{-40}$

If IEEE 754 is mentioned then for minimum we can't take E = 000..0 as E = 0 is reserved for special number.

0

https://docs.google.com/document/d/1y32_pAsYZ49fJM4Aim_qKjx4pCM-Lb-B9jZTyVDx1vg/edit

 

please check 36th question’s solution in this link

0
there no explicit form is mentioned like in this question.
0
Correct solution is given

Please log in or register to answer this question.

Related questions

0 votes
0 answers
4
Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,647 questions
56,497 answers
195,497 comments
100,828 users