1 votes 1 votes please provide a detailed solution CO and Architecture co-and-architecture cache-memory + – Vignaneswarkrishna asked Feb 1, 2019 retagged Jul 8, 2022 by Shubham Sharma 2 Vignaneswarkrishna 570 views answer comment Share Follow See all 10 Comments See all 10 10 Comments reply prashant jha 1 commented Feb 1, 2019 reply Follow Share Kindly type the problem , rather than posting it as a screenshot. 0 votes 0 votes gauravkc commented Feb 1, 2019 reply Follow Share Is it around 15? What am I supposed to take stall here? 29 and 59 😟 0 votes 0 votes prashant jha 1 commented Feb 1, 2019 reply Follow Share bhai L1 ka hit time kya liya @gauravkc 0 votes 0 votes gauravkc commented Feb 1, 2019 reply Follow Share 0. Usme koi stall nahi ana chahiye. Avg stall per inst pucha h, so. I might be wrong, not sure 😶 0 votes 0 votes prashant jha 1 commented Feb 1, 2019 reply Follow Share Im getting around 20. Taking L1 hit time 1 cycle. If there is no miss = 3 cycles / instruction. If there is miss :- Cycles taken = 1+1/9[30+1/2[60]] = 7.666666667 = 23 cycles / instruction Stalls = 23-3 = 20cycles. @gauravkc kaha galat hai bhai 0 votes 0 votes gauravkc commented Feb 1, 2019 reply Follow Share Maine try kiya k direct stalls nikle. hitL1 * 0 + 1/10 (0.5 * 30 + 0.5 * 60) 0.5*30 hona chahiye ya 30? out of the total miss (50% I'll face 30 cc + 50% I'll face 60 cc) 0 votes 0 votes prashant jha 1 commented Feb 1, 2019 reply Follow Share 30 bhai . agar 0.5 * 30 karra toh 0.5*(60+30) hona chaiye considering hierarchical access 0 votes 0 votes prashant jha 1 commented Feb 1, 2019 reply Follow Share aur isse stalls thodi aa rahe , isse toh cycles aa rahe . 🤔 0 votes 0 votes gauravkc commented Feb 1, 2019 reply Follow Share Oh ha correct. 60+30 ayega fir. Ha cycles aa rhe.. jane de chd 😂 0 votes 0 votes `JEET commented Nov 18, 2019 reply Follow Share Type the problem, please. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Ans is 20. ((50/450)*(30)+(25/450)*60)*3 =20. SaurabhKatkar answered Nov 18, 2019 SaurabhKatkar comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 3 memory reference = 1ins 1 memory reference = 1/3 ins 450 memory reference = 450*1/3=150 ins stall/ins=(miss l1/total no. of instruction) *hit L2+ (miss L2/total no. of instruction)* l2 miss = (50/150)*30+(25/150)*60 =10+10=20 Ans vishal23071998 answered Aug 9, 2020 vishal23071998 comment Share Follow See all 0 reply Please log in or register to add a comment.