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3 memory reference = 1ins

1 memory reference = 1/3 ins

450 memory reference = 450*1/3=150 ins

stall/ins=(miss l1/total no. of instruction) *hit L2+ (miss L2/total no. of instruction)* l2 miss

            = (50/150)*30+(25/150)*60     

            =10+10=20 Ans

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Ashwani Yadav asked Dec 6, 2018
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correct answer is 32.5 .why in the calculation, on cache miss, cache access time is not included?