edited by
412 views
2 votes
2 votes

The groups $Z_{9}$ and $Z_{3} \times  Z_{3}$ are 

  1. Isomorphic 
  2. Abelian
  3. Non abelian
  4. Cyclic 
edited by

1 Answer

0 votes
0 votes

Z is set of integer

But inverse of Z cannot be an integer value

So, in Z9 inverse cannot be an integer

So, it will be an nonabelian group

Answer will be (C) 

Related questions

2 votes
2 votes
1 answer
1
makhdoom ghaya asked Dec 9, 2015
677 views
There exists a group with a proper subgroup isomorphic to itself.
2 votes
2 votes
0 answers
2
makhdoom ghaya asked Dec 9, 2015
502 views
There is a non-trivial group homomorphism from $S_{3}$ to $\mathbb{Z}/3\mathbb{Z}$.
2 votes
2 votes
1 answer
3
makhdoom ghaya asked Dec 9, 2015
373 views
The symmetric group $S_{5}$ consisting of permutations on $5$ symbols has an element of order $6$.
1 votes
1 votes
0 answers
4
makhdoom ghaya asked Dec 9, 2015
355 views
There are n homomorphisms from the group $\mathbb{Z}/n\mathbb{Z}$ to the additive group of rationals $\mathbb{Q}$.