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+1 vote
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The function $f(x)$ defined by 

$f(x)
= \begin{cases}
ax+b & \text{x ≥ 1 }  \\
 x^{2}+3x+3& \text{x ≤ 1}  
\end{cases}$

is differentiable 

  1. For a unique value of a and infinitely many values of $b$. 
  2. For a unique value of $b$ and infinitely many values of $a$.
  3. For infinitely many values of $a$ and $b$.
  4. None of the above.
asked in Calculus by Veteran (43.6k points) | 89 views

1 Answer

0 votes
d) a=5

b=2
answered by Active (1.1k points)
Explain plz
Simply I did it like

continuous at 1 TF value , a+b=7

and also differntiable TF , diffrentiated and kept x=1

a=5


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