+1 vote
101 views

The function $f(x)$ defined by

$f(x) = \begin{cases} ax+b & \text{x ≥ 1 } \\ x^{2}+3x+3& \text{x ≤ 1} \end{cases}$

is differentiable

1. For a unique value of a and infinitely many values of $b$.
2. For a unique value of $b$ and infinitely many values of $a$.
3. For infinitely many values of $a$ and $b$.
4. None of the above.
asked in Calculus | 101 views

d) a=5

b=2
0
Explain plz
0
Simply I did it like

continuous at 1 TF value , a+b=7

and also differntiable TF , diffrentiated and kept x=1

a=5

+1 vote