1 votes 1 votes pream sagar asked Feb 3, 2019 pream sagar 1.7k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes Using K-map method we can reduce this to xnor and to implement xnor we will only need 3 nor gates if both inputs and their complements are available. Pankaj Joshi 3 answered Feb 3, 2019 Pankaj Joshi 3 comment Share Follow See all 5 Comments See all 5 5 Comments reply Hemanth_13 commented Feb 3, 2019 reply Follow Share Perfect.. it should be 3.. got worried after seeing few people posting answer as 4. :) 0 votes 0 votes Sayan Bose commented Feb 4, 2019 reply Follow Share Can you please upload the diag ? 0 votes 0 votes Nandkishor3939 commented Feb 4, 2019 reply Follow Share for how many marks this question was asked ?? 0 votes 0 votes Pankaj Joshi 3 commented Feb 4, 2019 reply Follow Share Here it is 1 votes 1 votes Pankaj Joshi 3 commented Feb 4, 2019 reply Follow Share @Nandkishor3939 it was of 2 marks.. NAT type 0 votes 0 votes Please log in or register to add a comment.
–1 votes –1 votes My answer is 2 Sunny Kamra answered Feb 3, 2019 Sunny Kamra comment Share Follow See all 0 reply Please log in or register to add a comment.
