# TIFR-2011-Maths-A-19

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The derivative of the function

$\int_{0}^{\sqrt{x}} e^{-t^{2}}dt$

at $x = 1$ is $e^{-1}$ .
in Calculus

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No the Answer is $\frac{1}{2} e^{-1}$... Apply Leibniz Rule

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