1 votes 1 votes The derivative of the function $\int_{0}^{\sqrt{x}} e^{-t^{2}}dt$ at $x = 1$ is $e^{-1}$ . Calculus tifrmaths2011 calculus differentiation + – makhdoom ghaya asked Dec 9, 2015 makhdoom ghaya 576 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes No the Answer is $\frac{1}{2} e^{-1}$... Apply Leibniz Rule seetal samal answered Nov 25, 2019 seetal samal comment Share Follow See all 0 reply Please log in or register to add a comment.