Operation systems exam 2019

Question

If the memory is 768 MB and the block’s size is 384 Bytes, what will be the size of the bitmap in Bytes?

I think it should be 2^21 Bytes, but I’m not quite sure.

Could you show me also your solution?

Answer 1

The total number of blocks would be 768MB/384B=2MB

In bit map each block is represented with a bit(1-the block is in use,0-block is in use),so there will 2^21 bits

which means the size of bitmap is 2^21/2^3 = 2^18 bytes.

So yes you are right,but it had to be 2^21 bits rather than bytes.