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ISRO Recruitment 2019

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When ISRO 2019 form filling will start?
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srestha asked May 28, 2019
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The value of $\sin 120^{o}+\sin 780^{o}-\cos 360^{o}$ $=(\sin (90^{o}\times 2)-60^{o})+\left ( \sin \left ( 90^{o}\times 8 \right )+60^{o} \right )-\left ( \cos (90^{o}\times 4)+0^{o} \right )$ $=\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}-1=0.73$ right??
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