32 votes 32 votes Consider three $4$-variable functions $f_1, f_2$, and $f_3$, which are expressed in sum-of-minterms as $f_1=\Sigma(0,2,5,8,14),$ $f_2=\Sigma(2,3,6,8,14,15),$ $f_3=\Sigma (2,7,11,14)$ For the following circuit with one AND gate and one XOR gate the output function $f$ can be expressed as: $\Sigma(7,8,11)$ $\Sigma (2,7,8,11,14)$ $\Sigma (2,14)$ $\Sigma (0,2,3,5,6,7,8,11,14,15)$ Digital Logic gatecse-2019 digital-logic k-map digital-circuits 2-marks + – Arjun asked Feb 7, 2019 edited Nov 30, 2022 by Lakshman Bhaiya Arjun 14.2k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes f1*f2 = ∑(2,8,14) f3 = ∑(2,7,11,14) f1*f2 ⊕ f3 = ∑(2,8,14) ⊕ ∑(2,7,11,14) = ∑(8,7,11) (Note: Choose the terms which are not common) varunrajarathnam answered Feb 8, 2021 varunrajarathnam comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes f1=Σ(0,2,5,8,14)^f2=Σ(2,3,6,8,14,15) =Σ(2,8,14) now (f1 ^ f2)⊕f3 =Σ(2,8,14)⊕Σ(2,7,11,14) =Σ(7,8,11) Chiranjeet mandal answered Jan 24, 2020 Chiranjeet mandal comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes AND gate takes common form both the terms and xor is inequality detector i .e. it gives output of those terms which are not common in both of the sop. So, answer is A. Jhaiyam answered Aug 22, 2020 Jhaiyam comment Share Follow See all 0 reply Please log in or register to add a comment.