$(A_{15} \: A_{14} \: A_{13} \: A_{12} \: A_{11} \: A_{10} \: A_9 \: A_ 8 \: A_7 \: A_6 \: A_5 \: A_4 \: A_3 \: A_2 \: A_1 \: A_0)$
According to question:
$A_{15} = 1, \: A_{14} = 1, \: A_{13} = 0, \: A_{12} = 0, \: A_{11} = 1$
So the possible range in binary:
$(\bf{1 1 0 0 1}$$ 0 0 0 0 0 0 0 0 0 0 0) \text{ to } (\bf{1 1 0 0 1}$$ 1 1 1 1 1 1 1 1 1 1 1)$
Converting to Hexadecimal:
$(C800) \text{ to } (CFFF)$
Option A.