0 votes 0 votes $\sum_{k=0}^{\propto }\left ( \sum_{j=0}^{k}1 \right )x^{k} = \sum_{k=0}^{\propto}(k+1)x^{k}$ How LHS=RHS here? Mathematical Logic discrete-mathematics + – Reshu $ingh asked Feb 8, 2019 Reshu $ingh 327 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Shaik Masthan commented Feb 8, 2019 reply Follow Share why you think those are not equal ? 1 votes 1 votes Reshu $ingh commented Feb 8, 2019 reply Follow Share @Shaik Masthan Mmm Not able to get how (k+1) has come... 0 votes 0 votes Shaik Masthan commented Feb 8, 2019 reply Follow Share left hand side if k=1, then j=0,j=1 two times 1 will be add ==> 1+1 right hand side, k=1, it will give 1+1 in general, left hand side, if k=i, then j=0,j=1,...j=i ==> total i+1 times 1 will be add right hand side, k=i, it will give i+1 3 votes 3 votes Reshu $ingh commented Feb 8, 2019 reply Follow Share Thanks.Got it now @Shaik Masthan 0 votes 0 votes Please log in or register to add a comment.