0 votes 0 votes In Single Precision floating point number when E=0 and M not equals to 0 it represents a fractional form..(BiAS=+127) when writing the decimal form why do we right (-1)^S * (1.M) * 2^(-126) instead of (-1)^S * (1.M) * 2^(-127)?? Digital Logic digital-logic number-representation ieee-representation floating-point-representation self-doubt + – DIYA BASU asked Feb 10, 2019 recategorized Jul 8, 2022 by Shubham Sharma 2 DIYA BASU 474 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes @DIYA I feel you should take it as (-1)^S * (1.M) * 2^(E-127) for single precision because this is the format prescribed by IEEE . The actual exponent is biased by 127 to get E that is the actual value of the exponent is E − 127. This gives the range: $2^{1-127}=2^{-126} \, to \,\, 2^{254-127}=2^{127}$ . _shashi answered Feb 11, 2019 _shashi comment Share Follow See all 0 reply Please log in or register to add a comment.