0 votes 0 votes Let 3 cards are drawn from a pack of 52 cards one by one without replacement then find the prob that 3 cards are drawn out of which 2 are ace Ace and one is King? rtalwar asked Feb 13, 2019 rtalwar 562 views answer comment Share Follow See all 11 Comments See all 11 11 Comments reply Show 8 previous comments Arko Jyoti Shith commented Feb 15, 2019 reply Follow Share why is simply 4C2*4C1/52C3 wrong here? 0 votes 0 votes rtalwar commented Feb 15, 2019 reply Follow Share Actually the answer should be 4c2*4c1*3!/52*51*50 ,the reason we do not choose 52c3 is because of conditional probability and also the 3! is not 3!/2! because in probability we consider ace as different so there are 3! Permutations and in selection we cannot do ordering therefore 4c2*4c1 1 votes 1 votes Shaik Masthan commented Feb 15, 2019 reply Follow Share yes it should be 3! only but not $\frac{3!}{2!}$ due to ACE cards can be differentiate ! Thanks for correcting me @rtalwar 1 votes 1 votes Please log in or register to add a comment.