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Let the subset be denoted as a n-bit sequence of 0s and 1s

A 0 at the ith position indicates absence of the ith element

A 1 at the jth position indicates presence of the jth element

For example, let the set be {1,2,3}

Then {1,2} can be represented as 110

{1,2,3} can be represented as 111

and so on

 

Now the number of subsets of even cardinality in an n-element set  = number of n bit strings with an even number of ones

 number of n bit strings with an even number of ones = number of n bit strings with an odd number of ones

=>  number of n bit strings with an even number of ones = (number of different n bit strings)/2 = $2^{n-1}$

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