in Programming
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2 votes
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#include <stdio.h>
char *c[] = {"GatsQuiz", "MCQ", "TEST", "QUIZ"};
char **cp[] = {c+3, c+2, c+1, c};
char ***cpp = cp;
int main()
{

printf("%s ", **++cpp);
printf("%s ", *--*++cpp+3);
printf("%s ", *cpp[-2]+3);
printf("%s ", cpp[-1][-1]+1);
return 0;

}

what is the output of this program? Please explain with reasons.

in Programming
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2 Comments

1
1

Useful link @Satbir

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0

1 Answer

3 votes
3 votes
Best answer

Based on the precedence of operators, given in https://en.cppreference.com/w/c/language/operator_precedence

Assuming size of pointer takes 8 Bytes, and Character takes 1 Byte.


we can evaluate the expressions in the program as follows:

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