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Answer : 20.

Consider two teams A and B.

For simplicity, I'm assuming A is winning playoff.

So, the number of ways for winning A is:

-Winning first 3 games $\rightarrow$ 1 way

-Winning at the end of 4th game $\rightarrow$ 3C2=3 ways

-Winning at the end of 5th game $\rightarrow$ 4C2=6 ways

Total number of matches in which A can win = 1+3+6 = 10 ways

Similarly, total number of matches in which B can win = 10

$\therefore$  different ways in which playoff can occur = 10 + 10 = 20

1 votes
1 votes
Let the two teams be A and B.

Consider the ways in which A can win

AAA
AABA
AABBA
ABAA
ABABA
ABBAA
BAAA
BAABA
BABAA
BBAAA

Thus A can win in 10 ways which is equal to choosing 3 As out of 5 slots

A can win in $\binom{5}{3}$ = 10 ways

B can also win in $\binom{5}{3}$ =  10 ways

Number of different playoffs = 10 + 10 = 20

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