NPTEL CODING ASSIGNMENT

Question

Consider a matrix M of integers. Divide M into 4 sub-matrices. These sub-matrices are called as Quadrants. Report the Quadrant number which has the smallest minimum-element. If two or more quadrants have same smallest minimum, report the smallest quadrant index.
The matrix M is divided into four quadrants by halving the rows and columns. If row/column is an odd number, divide them in such a way that the first half of the row/column should be one smaller than the second half.

The four quadrants are numbered from 1 to 4 in the structure shown below:

Q1 | Q2
---  + ---
 Q3 | Q4
INPUT FORMAT: M is a matrix of integers. You would be given two numbers m and n specifying the number of rows and columns. This would be followed by m lines of n integers each specifying the data of the m*n matrix M.
n and m will be greater than 1 and less than 12

 OUTPUT FORMAT: Print in a separate line, the quadrant number with the smallest minimum-element.

 

 

Comments

the rule is :

Before posting any question on programming, you should also comment where you struck otherwise upto where you reached !

if you doesn't follow, then someone could give their way of analysis, you have to blindly follow them !

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I haven't understand the problem itself,please explain your approach to tackle this!

Answer 1

#include<stdio.h>
int main()
{
   int m, n, c, d, matrix[10][10], minimum;
  scanf("%d%d",&m,&n);
  
   for( c = 0 ; c < m ; c++ )
   {
      for( d = 0 ; d < n ; d++ )
      {
         scanf("%d",&matrix[c][d]);
      }
   }
   
   minimum = matrix[0][0];
 
   for( c = 0 ; c < m ; c++ )
   {
      for( d = 0 ; d < n ; d++ )
      {
         if ( matrix[c][d] > minimum )
            minimum = matrix[c][d];
      }
   }
 
   printf("%d",minimum);
 
   return 0;
}

//I tried this much only..