0 votes 0 votes Consider a disk with an average seek time of $4$ ms. Motor speed 15000RPM 512B sector 500 sector per track A file occupies all of the sectors on $5$ tracks Each track reading requires average seek time and average rotational delay What will be transfer time of $1$ track? Operating System ace-test-series operating-system disk + – srestha asked Mar 7, 2019 edited Mar 7, 2019 by akash.dinkar12 srestha 520 views answer comment Share Follow See all 7 Comments See all 7 7 Comments reply srestha commented Mar 7, 2019 reply Follow Share @Shaik Masthan @ankitgupta.1729 plz verify 0 votes 0 votes ankitgupta.1729 commented Mar 7, 2019 reply Follow Share mam, I think transfer rate/speed should be given in question. Transfer time for 1 track = (total data available in 1 track)/ Transfer speed = (500*512 Bytes)/ transfer speed. If we consider that data of 1 track is transferred in 1 rotation. Then 15000 RPM means 15000 rotations in 1 minute (or) 1 rotation in 1/15000 minutes (or) data of 1 track can be transferred in 1/15000 minutes. 0 votes 0 votes srestha commented Mar 7, 2019 reply Follow Share @ankitgupta.1729 then what will be answer (500*512 Bytes)/ transfer speed.? or 1/15000 minutes. ? 0 votes 0 votes srestha commented Mar 7, 2019 reply Follow Share if we take a real life example Can we think transfer time means transfer time means just some byte is transferring? What is transfer time actually means? 0 votes 0 votes ankitgupta.1729 commented Mar 7, 2019 reply Follow Share mam, 1/15000 min since transfer rate is not given. Here , Arjun sir also has done the same thing. transfer time simply means time taken to transfer some data from one place to other. 0 votes 0 votes abhishekmehta4u commented Mar 8, 2019 reply Follow Share Ii am getting 30.04 0 votes 0 votes srestha commented Mar 8, 2019 reply Follow Share how? It is asking for 1 track 1 track means 500 sector and 1 sector can store 512B 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes 1 rotation time = 4ms 1 track rotation time=4ms 1 sector rotation time=4/500 ms = 8microsec So, transfer time of sector=1sector rotation time =8microsecond Sajal Mallick answered Aug 26, 2023 Sajal Mallick comment Share Follow See all 0 reply Please log in or register to add a comment.