1 votes 1 votes in selective repeat(SR) protocol the sender window size is K frames. What is the number of sequence bits required for the communication to take place? $log_2$(k+1) 1+$log_2$k 1+$log_2$(2k) None himgta asked Mar 10, 2019 himgta 670 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Abhisek Tiwari 4 commented Mar 10, 2019 reply Follow Share in SR protocol SWS=RWS i.e k+k=2k sequence no log(2k) =1+logk so 2. 0 votes 0 votes himgta commented Mar 10, 2019 reply Follow Share how $log_2$2k is 1+log k?? 0 votes 0 votes Abhisek Tiwari 4 commented Mar 10, 2019 reply Follow Share logmn=logm + logn log(base a) a=1 0 votes 0 votes himgta commented Mar 10, 2019 reply Follow Share I saw 2k in option C and marked that! 😐 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes option 2 is right. abhishekmehta4u answered Mar 10, 2019 abhishekmehta4u comment Share Follow See all 0 reply Please log in or register to add a comment.
