0 votes 0 votes closed with the note: no source A(n) {if(n<1) return (1); else return A(n-2)+B(n-1);} B(n) {if(n<=1) return 1; else return B(n-1)+A(n-2);} Nishi Agarwal asked Mar 10, 2019 • closed Mar 10, 2019 by Arjun Nishi Agarwal 506 views comment Share Follow See 1 comment See all 1 1 comment reply noob_coder commented Mar 10, 2019 reply Follow Share It can be solved by drawing recursive tree. 0 votes 0 votes Please log in or register to add a comment.