0 votes 0 votes If the halting problem were decidable, then every recursively enumerable language would be recursive. Consequently, the halting problem is undecidable. Describe in detail how $H$ in given Theorem can be modified to produce $H^{\prime} $. Theory of Computation peter-linz peter-linz-edition5 decidability theory-of-computation + – Rishi yadav asked Mar 14, 2019 • retagged Mar 14, 2019 by Rishi yadav Rishi yadav 230 views answer comment Share Follow See 1 comment See all 1 1 comment reply himgta commented Mar 15, 2019 reply Follow Share If the halting problem were decidable,then every recursively enumerable language would be recursive but we know that there is at least one language that is recursive enumerable but not recursive ,hence we arrive at the contradiction Therefore halting problem must be undecidable! 0 votes 0 votes Please log in or register to add a comment.