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Bandwidth=64 Kbits/sec

Frame size=512 Bytes

Transmission Delay($T_{t}$)=$\frac{512*8}{64*10^3}$=64 ms

Propagation Delay($T_{t}$)=270 ms

a=$\frac{T_{p}}{T_{t}}$

Throughput or Bandwidth utilization=Efficiency*Bandwidth=$\frac{N}{1+2a}*Bandwidth=\frac{N}{1+2a}*64 Kbits/sec$

N | Efficiency | Throughput |

1 | 10.59% | 6.78 Kbits/sec |

7 | 74.17% | 47,470 bits/sec |

9 | 95.36% | 61,033 bits/sec |

For window size 10 or greater the channel utilization will be 100% and throughput will be 64 Kbits/sec

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