2 votes 2 votes Show that $\exists x P(x) \wedge \exists x Q(x)$ and $\exists x (P(x) \wedge Q(x))$ are not logically equivalent. Mathematical Logic kenneth-rosen discrete-mathematics mathematical-logic propositional-logic + – Pooja Khatri asked Mar 18, 2019 • edited May 2, 2019 by Pooja Khatri Pooja Khatri 244 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.