1 votes 1 votes Consider the effect of using slow start on a line with a 10-msec round-trip time and no congestion. The receive window is 24 KB and the maximum segment size is 2 KB. How long does it take before the first full window can be sent? Computer Networks computer-networks tanenbaum transport-layer tcp congestion-control + – ajaysoni1924 asked Mar 18, 2019 ajaysoni1924 776 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes Starting with window size = 1 segment = 2 KB At RTT 1 (10 ms), cwnd = 4 KB At RTT 2 (20 ms), cwnd = 8 KB At RTT 3 (30 ms), cwnd = 16 KB At RTT 4 (40 ms), cwnd = 24 (limited by receiver window) Answer = 40 ms Avinash31 answered Sep 30, 2020 Avinash31 comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes RCWD=24/2=12 Thresh hold=12/2=6 set 1 ,2, 4, 6, 7, 8, 9, 10, 11, 12 total 9*10=90 ms before send full window 12 raju paul answered Nov 3, 2019 raju paul comment Share Follow See 1 comment See all 1 1 comment reply sridhar15399 commented Jul 16, 2021 reply Follow Share No congestion is given in que so it should always work on slow start mode 2 votes 2 votes Please log in or register to add a comment.
