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A TCP machine is sending full windows of 65,535 bytes over a 1-Gbps channel that
has a 10-msec one-way delay. What is the maximum throughput achievable? What is
the line efficiency?
in Computer Networks by Boss (11k points) | 64 views

1 Answer

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One way delay=10 ms, RTT=20 ms

In 1 sec, we can send 1Gb of data=$10^9$ bits

In 20 ms we can send $\frac{20*10^9}{10^3}=20$ Mb of data

But we're sending only 65,535 Bytes of data [1 full window transmitted in 1 RTT]

Efficiency=$\frac{65535*8}{20*10^6}*100$=2.62%
by Loyal (5.2k points)

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