we have a page of size 1KB which is 1024 bytes
Page 0 will contain page numbers from 0 to 1023
So by dividing the addresses by 1024 and taking their floor values we can easily calculate the page number
a.base(3085/1024)=3
b.baae(42095/1024)=41
c.base(215201/1024)=210
d. base(650000/1024)=634
e base(2000001/1024)=1953
Note:If page number starts from 1 we will start taking the ceil values...but it's totally hypothetical