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Is it true?

$an^{2} = O(n^{2})$  for a>0

Also, what is the difference between Small-oh and Big-oh?

Also, why we consider theta, omega as Big-oh sometimes, in the above problem, the answer is Big-theta but it is equal to big-oh. Why is it so?

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sumit goyal 1 asked Dec 23, 2017
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given : 1/4 and 1 1/4 = theta(1)is this corrector only this 1/4 = O(1)