0 votes 0 votes Find the no. of permutations of the letters of the word ‘REMAINS’ such that the vowels always occur in odd places? Dipanshu Rana asked Mar 21, 2019 Dipanshu Rana 474 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Shaik Masthan commented Mar 22, 2019 reply Follow Share when you are practicing, please first, write down your solution along with the question ! 0 votes 0 votes Dipanshu Rana commented Mar 22, 2019 reply Follow Share Ans given is 576 0 votes 0 votes Shaik Masthan commented Mar 22, 2019 reply Follow Share i am not asking answer ! show the work, what you did !! 0 votes 0 votes balchandar reddy san commented Apr 27, 2019 reply Follow Share REMAINS { 3 vowels, 4 consonants} _ _ _ _ _ _ _ (o e o e o e o) { 4 odd , 3 even positions } number of ways = 4c3 * 3! * 4! = 576 (chosing 3 out of 4 odd positions for vowels) * (arranging those 3 vowels) * (arranging 4 consonants) 0 votes 0 votes Please log in or register to add a comment.