$1)F(A,B,C)=(AB+C)(B+\overline{C}D)$
we can write like this
$F(A,B,C)=AB+AB\overline{C}D+CB+C.\overline{C}D$
$F(A,B,C)=AB+AB\overline{C}D+BC$
Sum of Product form(SOP)
$F(A,B,C)=AB\cdot 1\cdot 1+AB\overline{C}D+1\cdot BC\cdot 1$
$F(A,B,C)=AB(C+\overline{C})(D+\overline{D})+AB\overline{C}D+(A+\overline{A})BC(D+\overline{D})$
$F(A,B,C)=(ABC+AB\overline{C})(D+\overline{D})+AB\overline{C}D+(ABC+\overline{A}.BC)(D+\overline{D})$
$F(A,B,C)=ABCD+AB\overline{C}D+ABC\overline{D}+AB\overline{C}\cdot\overline{D}+AB\overline{C}D$
$+ABCD+ABC\overline{D}+\overline{A}BCD+\overline{A}BC\overline{D}$
${\color{DarkOrange}{F(A,B,C)=ABCD+AB\overline{C}D+ABC\overline{D}+AB\overline{C}\cdot\overline{D}+\overline{A}BCD+\overline{A}BC\overline{D} }}$
Product of Sum form(POS)
$F(A,B,C)=(\overline{A}+\overline{B}+\overline{C}+\overline{D} )\cdot(\overline{A}+\overline{B}+C+\overline{D})\cdot$
$(\overline{A}+\overline{B}+\overline{C}+D)\cdot(\overline{A}+\overline{B}+C+D)+(A+\overline{B}+\overline{C}+\overline{D})+(A+\overline{B}+\overline{C}+D)$
$2)F(X,Y,Z)=X+X(X+\overline{Y})(Y+\overline{Z})$
we can write like this
$2)F(X,Y,Z)=X+(X+X\overline{Y})(Y+\overline{Z})$
$F(X,Y,Z)=X+XY+X\overline{Z}+X\overline{Y}Y+X\overline{Y}\cdot\overline{Z}$
$F(X,Y,Z)=X+XY+X\overline{Z}+X\overline{Y}\cdot\overline{Z}$
Sum of Product form(SOP)
$F(X,Y,Z)=X(Y+\overline{Y})(Z+\overline{Z})+XY(Z+\overline{Z})+X(Y+\overline{Y})Z+X\overline{Y}\cdot\overline{Z}$
$F(X,Y,Z)=(XY+X\overline{Y})(Z+\overline{Z})+XYZ+XY\overline{Z}+XYZ+X\overline{Y}Z+X\overline{Y}\cdot\overline{Z}$
$F(X,Y,Z)=XYZ+XY\overline{Z}+X\overline{Y}Z+X\overline{Y}\cdot\overline{Z}+XYZ+XY\overline{Z}+X\overline{Y}Z+X\overline{Y}\cdot\overline{Z}$
${\color{Magenta}{F(X,Y,Z)=XYZ+XY\overline{Z}+X\overline{Y}Z+X\overline{Y}\cdot\overline{Z}} }$
Product of Sum form(POS)
$F(X,Y,Z)=(\overline{X}+\overline{Y}+\overline{Z})\cdot(\overline{X}+\overline{Y}+Z)$
$\cdot(\overline{X}+Y+\overline{Z})\cdot(\overline{X}+Y+Z)$
