0 votes 0 votes How is the problem.. Distribute 5 toys such that each of 3 child get atleast 1 Different from sum of 3 no. X+y+z=5 such that each digit >= 1. Plz explain ? Combinatory combinatory + – Manoj Kumar Pandey asked Apr 4, 2019 Manoj Kumar Pandey 647 views answer comment Share Follow See all 9 Comments See all 9 9 Comments reply tusharp commented Apr 4, 2019 reply Follow Share 150 for first and 6 for the second? 1 votes 1 votes Manoj Kumar Pandey commented Apr 4, 2019 reply Follow Share How do we need to approach both problems differently plz give some insight.. Do we need to take candies to be distinct or how do we approach? 0 votes 0 votes tusharp commented Apr 4, 2019 reply Follow Share 1. For the first one, I have considered toys to be different. When objects to be distributed are greater than the available persons and each should get at least one, we cannot do give one to each and then permute remaining anyhow. Here comes the concept of grouping and distribution. 2. The second one is the permutation of star and bars with extra criteria of having at least one from each. Take one from each which makes the equation as X' + Y' + Z' = 2 (Two stars and two bars) 0 votes 0 votes Shaik Masthan commented Apr 4, 2019 reply Follow Share actually, it is questioner responsibility to give toys are identical or not ? 0 votes 0 votes tusharp commented Apr 5, 2019 reply Follow Share Question will give the hint for the same 0 votes 0 votes Shaik Masthan commented Apr 5, 2019 reply Follow Share unfortunately, i didn't get it from the question 0 votes 0 votes Manoj Kumar Pandey commented Apr 5, 2019 reply Follow Share This way for the first case we can manually find the cases but how do we do if the no. To be distributed is large say 12 0 votes 0 votes tusharp commented Apr 5, 2019 reply Follow Share shaik bro I meant the questions in the exam will give the hint:). This one is ambiguous. 1 votes 1 votes tusharp commented Apr 5, 2019 reply Follow Share @Manoj Kumar Pandey refer Rosen or do combinatorics from here. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes don't over think this can be done manually give all student one toy first x= 1 y=1 z=1 now you are left with 2 more toys i think you can distribute 2 among three easily x y z 2 0 0 0 2 0 0 0 2 1 1 0 1 0 1 0 1 1 ANS=6 correct me if I am wrong..... hitendra singh answered Apr 4, 2019 hitendra singh comment Share Follow See all 0 reply Please log in or register to add a comment.