0 votes 0 votes How is the problem.. Distribute 5 toys such that each of 3 child get atleast 1 Different from sum of 3 no. X+y+z=5 such that each digit >= 1. Plz explain ? Combinatory combinatory + – Manoj Kumar Pandey asked Apr 4, 2019 Manoj Kumar Pandey 623 views answer comment Share Follow See all 9 Comments See all 9 9 Comments reply Show 6 previous comments Manoj Kumar Pandey commented Apr 5, 2019 reply Follow Share This way for the first case we can manually find the cases but how do we do if the no. To be distributed is large say 12 0 votes 0 votes tusharp commented Apr 5, 2019 reply Follow Share shaik bro I meant the questions in the exam will give the hint:). This one is ambiguous. 1 votes 1 votes tusharp commented Apr 5, 2019 reply Follow Share @Manoj Kumar Pandey refer Rosen or do combinatorics from here. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes don't over think this can be done manually give all student one toy first x= 1 y=1 z=1 now you are left with 2 more toys i think you can distribute 2 among three easily x y z 2 0 0 0 2 0 0 0 2 1 1 0 1 0 1 0 1 1 ANS=6 correct me if I am wrong..... hitendra singh answered Apr 4, 2019 hitendra singh comment Share Follow See all 0 reply Please log in or register to add a comment.