0 votes 0 votes Use a proof by contraposition to show that if $x+y≥2$,where $x$ and $y$ are real numbers, then $x≥1$ or $y≥1$. Mathematical Logic kenneth-rosen discrete-mathematics mathematical-logic propositional-logic + – Pooja Khatri asked Apr 4, 2019 Pooja Khatri 469 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Let us assume the contrapositive, i.e both $x,y$ are less than $1$. Now, we are given the fact that $x+y\ge 2$, but from our assumption that $x<1$ and $y<1$, we get that $x+y<2$ which defies our given fact. vedantbonde19 answered Jan 5, 2020 vedantbonde19 comment Share Follow See all 0 reply Please log in or register to add a comment.