0 votes 0 votes Suppose we have an application A1 and 2 application from different applications wants to connect with it then does the computer containing the values have 2 threads of application A1 or it calls the fork() system call and creates a child process?? Doraemon asked Apr 8, 2019 Doraemon 291 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply srestha commented Apr 8, 2019 reply Follow Share why network connection needs process creation? 0 votes 0 votes Doraemon commented Apr 8, 2019 reply Follow Share suppose you have a client A and server B when host A sends 2 an http request to B using TCP at TL then only the application at port 80 will respond now if the application at port 80 is already servicing the first http request then how will it respond to the second http request.......Here we have to create another thread/child process (which I want to know ) of the actual process and assign it another port number in the server machine and make the client know that the server program will be accessable from the newly created port during the connection establishment phase when we use TCP. CORRECT ME IF I AM WRONG. 0 votes 0 votes Doraemon commented Apr 8, 2019 i edited by Doraemon Apr 8, 2019 reply Follow Share @srestha 0 votes 0 votes srestha commented Apr 8, 2019 reply Follow Share I am not getting ur doubt clearly But still my view is Say if u want to check Google page,the page will load within few seconds. But these are not only one page created by programmer. Programmer created a page and loaded it in Google server. And we user just getting it's view only. Now how server know, we want that page? So, we send our request through some message and those message breaks up in small packets. and request the google server to create a view. And port are mainly in transport layer .I have not a good idea how those port works. But I think any protocol have more than one port like FTP has 80 and 81 two renouned port. So, port is not a problem for request servicing 0 votes 0 votes Please log in or register to add a comment.