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Suppose users share a 2 Mbps link. Also, suppose each user transmits continuously at 1 Mbps when transmitting, but each user transmits only 20 percent of the time.

  1. When circuit switching is used, how many users can be supported?
  2.  For the remainder of this problem, suppose packet switching is used. Why
    will there be essentially no queuing delay before the link if two or fewer
    users transmit at the same time? Why will there be a queuing delay if
    three users transmit at the same time?
  3.  Find the probability that a given user is transmitting.
  4. Suppose now there are three users. Find the probability that at any given
    time, all three users are transmitting simultaneously. Find the fraction of
    time during which the queue grows.

1 Answer

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  1. When the circuit switching is used 2 users can transmit because users share the 2 Mbps connection and 1 user uses 1 Mbps so half-half is utilized.
  2. if 2 or fewer means 1 or o user are transmitting that means they do not require any additional bandwidth  so no queuing delay, if three users transmit at the same time then queuing delay will occur.
  3. 1/5 =0.2
  4. (0.2)^3 = 0.008

 

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