301 views

2 Answers

0 votes
0 votes
Given $f(x)= x^3 + 1$

Let $y=f(x)$

$y=x^3+1$

$x=y^3+1$

$y^3=x-1$

$ y=\sqrt[3]{x-1}$
0 votes
0 votes

The inverse of function:

  • $f$ is a bijection ,$f_{A\rightarrow B}$
  • $f^{-1}$ is a bijection ,$f_{B\rightarrow A}$
  • $f^{-1}_{B\rightarrow A}(x) = y$   iff  $f_{A\rightarrow B}(y) = x$

Given that $f(x) = x^{3} + 1$

$f^{-1}(x) = y \ $ iff $\ f(y) = x$

$\implies y^{3} + 1 = x$

$\implies y^{3} = x - 1$

$\implies y = \sqrt[3]{x-1}$

Related questions

0 votes
0 votes
0 answers
1
0 votes
0 votes
0 answers
2
0 votes
0 votes
1 answer
3
Pooja Khatri asked Apr 11, 2019
303 views
Suppose that $f$ is a function from $A$ to $B$, where $A$ and $B$ are finite sets with $|A|=|B|$. Show that $f$ is one-to-one if and only if it is onto.