4 votes 4 votes Let X∈{0,1} and Y∈{0,1} be two random variables if P(X=0) =p and P(Y=0)=q then P(X+Y>=1) is equal to 1)pq+(1-p)(1-q) 2)pq 3)p(1-q) 4)1-pq Probability probability random-variable easy + – Pooja Palod asked Dec 15, 2015 Pooja Palod 515 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 6 votes 6 votes X∈{0,1} Y∈{0,1} i.e. for P(X+Y>=1) value of X and Y can be {(0,1),(1,0),(1,1)} So we can say , P(X+Y>=1) = 1-P(X+Y<1) = 1- P(X=0,Y=0) =1- {P(X=0).P(Y=0)} =1-pq srestha answered Dec 15, 2015 • selected Dec 27, 2015 by Himanshu1 srestha comment Share Follow See 1 comment See all 1 1 comment reply Lakshman Bhaiya commented Dec 3, 2018 reply Follow Share @srestha ma'am Here $X$ and $Y$ should be an independent random variable. Because $P[(X=0) \cap (Y=0)]=P[X=0].P[Y=0]$ 0 votes 0 votes Please log in or register to add a comment.
