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Suppose Host A sends two TCP segments back to back to Host B over a TCP connection. The first segment has sequence number 90; the second has sequence number 110.

  1. How much data is in the first segment?
  1. Suppose that the first segment is lost but the second segment arrives at B. In the acknowledgment that Host B sends to Host A, what will be the acknowledgment number?
asked in Computer Networks by Loyal (9.7k points) | 53 views

1 Answer

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The sequence number of the first Byte of first segment  = 90 and The sequence number of the first Byte of second segment  = 110

which implies, The sequence number of the last Byte of first segment  = 109.

(A) Therefore number of Bytes in the segment is (109-90+1 = 20)


(B) Ack number will be 90. since the first segment is lost
answered by (431 points)

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