1 votes 1 votes Consider a $n \times n$ matrix $A=I_n-\alpha\alpha^T$, where $I_n$ is the $n\times n$ identity matrix and $\alpha$ is an $n\times 1$ column vector such that $\alpha^T\alpha=1$.Show that $A^2=A$. Linear Algebra isi2018-pcb-a engineering-mathematics linear-algebra matrix descriptive + – akash.dinkar12 asked May 12, 2019 akash.dinkar12 519 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes Proof is in the image. Kaustubh Vande answered May 20, 2019 Kaustubh Vande comment Share Follow See all 0 reply Please log in or register to add a comment.