+1 vote
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What will be solution of recurrence relation if roots are like this: r1=-2, r2=2, r3=-2, r4=2
is this the case of repetitive roots?

edited | 67 views
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simply, $(\alpha - (-2))^{2}(\alpha -2)^{2} = 0$
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sorry
i meant the solution of the recurrence relation with co-efficient and root
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how one can find out the solution without knowing recurrence relation,  base conditions and whether it is homogeneous or non-homogeneous ??

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i'm asking for the equation with co-efficients and root
for example

if the roots are 2 and 3 then the equation will be A*2^n+B*3^n

and it the roots are 2 and 2 then the equation will be A*2^n+B*n*2^n

if root 2 is repeated for 2 times then A.2^n+B.n.2^n
like that for root = -2
by (349 points)
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can u give the whole expression?
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May be this will help (start from 14:25)