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int main()
    int a = 10;
    int *b = &a;

What will be the Output of the following code if input given is $25$ ?

asked in Programming by (141 points)
edited by | 55 views

2 Answers

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int main() {
 int a=10;            // value of a =10;
 int *b=&a;          // pointer b stores the address of a i.e. points to a
 scanf("%d",b);     // b gets a value from user(25) and stores it in a since b points to a
 printf("%d",a+50);  // here a = (value which user gave + 50)= 25+50 = 75
 return 0;

$\therefore$ here value of $a$ = (value which user gave + 50) = 25+50 = $75$ will be printed as output.

answered by Boss (12.9k points)
I'm having a doubt that b contains address of a than how can we update the value of a as=25 rather than not updating any value
Plz help with an approach for my doubt.

scanf reads data from stdin(here it is 25) and stores them according to the parameter format (here it is %d) into the locations pointed by the additional arguments.(i.e stores in location pointed by b)

we generally write scanf as scanf("%d" , &a); and here b = &a;

So we can write scanf("%d",b);

0 votes

Output 75


answered by (33 points)

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