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Calculate the effective throughput for transferring a 1000 KB file assuming TCP using
slow start congestion control technique. Given the round trip time 100 ms, and maximum
segment size is 1460 bytes. Assume there are no losses and both the bandwidth and the
receiver window size is infinite.
  (A) 5MBPS
  (B) 10Mbps
  (C) 1MBPS
  (D) 1Mbps

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Here, maximum segment size(1 MSS)=1460B.,so in one RTT 1460 B is transferred.To send 1000KB we need 1000*1024/1460 MSS= 702 MSS (appx).

Using slow start algorithm,

                                          1 MSS |  2 MSS | 4 MSS | 8 MSS |  16 MSS | 32 MSS | 64 MSS | 128 MSS | 256 MSS |512 MSS | 1024MSS.So in total we need 10 RTT (10* 100 ms=1000 ms) to send 1000KB.

We know , throughput is the number of bytes sent per second.

So, to send 1000KB we need 1000 ms.So, in 1 sec, it will send 1000 Kb.

So,throughput =1000kbps=1 mbps(D)

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