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In a non-homogeneous equation Ax = b, x has a unique solution when $A^{-1}$ exists i.e  x = $A^{-1}$b

but when det(A) = 0 then we have infinite solution or many solution.

please give a mathematical explanation of how the 2nd statement occurs?
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In case of det(A)=0, either infinite solution or no solution exists..
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how is this happening???

I want to know this because of remembering
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