1 votes 1 votes A carnival swing ride swings to the left with probability 0.4 and to the right with probability. If the ride stops after 10 swings, what is the probability that it is exactly at the place it started? Probability probability sheldon-ross random-variable + – Asim Siddiqui 4 asked May 27, 2019 Asim Siddiqui 4 735 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments Arkaprava commented Jun 20, 2019 reply Follow Share I can't find any such question in sheldon ross, can you attach a screenshot ? 0 votes 0 votes Asim Siddiqui 4 commented Jun 26, 2019 reply Follow Share I'm attaching the image with this. It seems that question is misprinted but lets say if any value like 0.6(by intuition) is given then what will be the approach to solve such type of questions. 0 votes 0 votes Asim Siddiqui 4 commented Jun 26, 2019 reply Follow Share Q 4.43 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes If probability of moving right is also given , say p(r), then the swing will be at the same place, if the swing moves left and right equal no. of times=10/2 =5 . The answer should be $10C_5\times{p(r)}^5\times p(l)^5$ Arkaprava answered Jun 26, 2019 Arkaprava comment Share Follow See all 0 reply Please log in or register to add a comment.